How far does the object compress the spring

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WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer. Question: 2. A 1.5-kg object is held 1.2 … Web20 feb. 2011 · In the case of a spring, the force that one must exert to compress a spring 1m is LESS than the force needed to compress it 2m or 3m, etc. The force needed CHANGES; this is why we are …

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WebHow far does the object compress the spring if the same experiment is performed on the Moon, where g = 1.63 m/s2 and air resistance is neglected? arrow_forward. A student working on a school project modeled a trampoline as a spring obeying Hookes law and measured the spring constant of a certain trampoline as 4617 N/m. ctiweb

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Web12 aug. 2016 · No need to half it. You draw the free body diagram of the object at one end, and it shows a spring force. This force is the push, the spring exerts on the object because it is compressed a bit and tries to return to the uncompressed state. And it is experimentally found to be proportional to the compression as F = k x. WebHow far is the spring compressed ; A box of mass m = 1.50 kg is dropped from rest onto a massless, vertical spring with spring constant k = 2.35 \times 10^2 N/m that is initially at its natural length. How far is the spring compressed ; A 65-kg object is dropped from rest a distance of 4.3 m onto a spring with a stiffness coefficient of 6.2 x ... WebA 1.20-kg object is held 1.40 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (Hint: you will have to use … cti warrington

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Solved 2. A 1.5-kg object is held 1.2 m above a relaxed Chegg.com

WebA 1.40-kg object is held 1.25 m above a relaxed, massless vertical spring with a force constant of 300 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? Your response differs from the correct answer by more than 10%. WebA 1.40-kg object is held 1.25 m above a relaxed, massless vertical spring with a force constant of 300 N/m. The object is dropped onto the spring. (a) How far does the … cti weatherizationWebThe equation that relates the amount of elastic potential energy (PEspring) to the amount of compression or stretch (x) is. PE spring = ½ • k•x 2. where k is the spring constant (in … cti warren pa

"Web22 jul. 2024 · The initial gravitational potential energy of the object is: where. m = 1.50 kg is the mass of the object. g = 9.8 m/s^2 is the acceleration of gravity. h = 1.27 m is the height of the object. The final elastic potential energy of the compressed spring is. where. k = 300 N/m is the spring constant. x is the compression of the spring " - How far does the object compress the spring

How far does the object compress the spring

Compression of spring when an object of given mass is …

Web2 feb. 2024 · Let's consider the spring constant to be -40 N/m. Then the applied force is 28N for a 0.7 m displacement. The formula to calculate the applied force in Hooke's law … WebThe second approach gives the compression when the velocity of the object is zero. When the block falls on the spring, it oscillates between $x=\frac{2mg}{k}$ and $x = 0$. Since …

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WebIt till the block becomes motionless.The kinetic frictional force is 15 N.The spring constant: 100000 N/m.The spring compresses by Medium View solution > A 1.50−kg object is held 1.20m above a relaxed mass-less, vertical spring with a force constant of 320N/M The object is dropped onto the spring How far does the object compress the spring. Hard WebThe object has a speed of ν i=3.00m/s when it makes constant with a light spring Fig that has a force constant of 50.0N/m The object comes to rest after the spring has been …

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WebA 1.80-kg object is held 1.15 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? 0.396x Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. WebAnswer (1 of 2): I’ll assume that the 3.6m is the distance from the mass’s starting point to the top of the spring, and that the mass is initially stationary and just falls under gravity. Call x the distance the spring is compressed. So the mass drops through a …

WebTranscribed Image Text: A 1.60-kg object is held 1.30 m above a relaxed, massless vertical spring with a force constant of 315 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? (b) Repeat part (a), but this time assume a constant air-resistance force of 0.800 N acts on the object during its motion. m (c) …

WebA 1.50 kg object Is held 1.20 m above a relaxed, massless vertical spring with a force constant of 300 N/m. The object Is dropped onto the (a) How far does the object … earth newspaper vernon colemanWeb22 dec. 2024 · The good news it’s a simple law, describing a linear relationship and having the form of a basic straight-line equation. The formula for Hooke’s law specifically relates the change in extension of the spring, x , to the restoring force, F , generated in it: F = −kx F = −kx. The extra term, k , is the spring constant. earthnewspaper vernon colemanWeb22 dec. 2024 · The law essentially describes a linear relationship between the extension of a spring and the restoring force it gives rise to in the spring; in other words, it takes twice … cti waterfordWebThe second approach gives the compression when the velocity of the object is zero. When the block falls on the spring, it oscillates between x = 2 m g k and x = 0. Since the spring is ideal and the air resistance is negligible, this oscillation does not die down and so the question is wrong. ctiwebportalWeb[What happens when a spring is stretched too far?] Equations Hooke’s law The force required to stretch an elastic object such as a metal spring is directly proportional to the … cti wasteWeb26 nov. 2024 · The compression of the spring when air resistance is considered 0.36 m. The compression of the spring when air resistance is neglected and gravity is 1.63 is 0.14 m. … cti well service williston ndWeb2 aug. 2024 · A 1.30 kg object is held 1.20 m above a relaxed, massless vertical spring with a force constant of 310 N/m. The object is dropped onto the spring. (a) How far does the object compress the spring? ________m (b) How far does the object compress the spring if the same experiment is performed on the moon, where g = 1.63 m/s2? … cti webinars